Base | Representation |
---|---|
bin | 10010111100111000111… |
… | …011001100101100111101 |
3 | 11121111112121220111012211 |
4 | 102330320323030230331 |
5 | 132314133003231214 |
6 | 2434140542300421 |
7 | 163042645325062 |
oct | 22747073145475 |
9 | 4544477814184 |
10 | 1302330133309 |
11 | 4623514548a7 |
12 | 190497887711 |
13 | 95a69a9014a |
14 | 47066c1cc69 |
15 | 23d2379a0c4 |
hex | 12f38eccb3d |
1302330133309 has 2 divisors, whose sum is σ = 1302330133310. Its totient is φ = 1302330133308.
The previous prime is 1302330133289. The next prime is 1302330133327. The reversal of 1302330133309 is 9033310332031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 675113652409 + 627216480900 = 821653^2 + 791970^2 .
It is an emirp because it is prime and its reverse (9033310332031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1302330133309 is a prime.
It is a super-2 number, since 2×13023301333092 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1302330133339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651165066654 + 651165066655.
It is an arithmetic number, because the mean of its divisors is an integer number (651165066655).
Almost surely, 21302330133309 is an apocalyptic number.
It is an amenable number.
1302330133309 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302330133309 is an equidigital number, since it uses as much as digits as its factorization.
1302330133309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 31.
The spelling of 1302330133309 in words is "one trillion, three hundred two billion, three hundred thirty million, one hundred thirty-three thousand, three hundred nine".
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