Base | Representation |
---|---|
bin | 10010111100111000111… |
… | …011011111111100001011 |
3 | 11121111112122001111022021 |
4 | 102330320323133330023 |
5 | 132314133013241412 |
6 | 2434140544105311 |
7 | 163042646103601 |
oct | 22747073377413 |
9 | 4544478044267 |
10 | 1302330212107 |
11 | 4623514a9021 |
12 | 190497905237 |
13 | 95a69ab9c82 |
14 | 47066c3d871 |
15 | 23d237b3607 |
hex | 12f38edff0b |
1302330212107 has 2 divisors, whose sum is σ = 1302330212108. Its totient is φ = 1302330212106.
The previous prime is 1302330212017. The next prime is 1302330212111. The reversal of 1302330212107 is 7012120332031.
It is a happy number.
Together with previous prime (1302330212017) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is an emirp because it is prime and its reverse (7012120332031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1302330212107 - 219 = 1302329687819 is a prime.
It is not a weakly prime, because it can be changed into another prime (1302330212137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651165106053 + 651165106054.
It is an arithmetic number, because the mean of its divisors is an integer number (651165106054).
Almost surely, 21302330212107 is an apocalyptic number.
1302330212107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302330212107 is an equidigital number, since it uses as much as digits as its factorization.
1302330212107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 1302330212107 its reverse (7012120332031), we get a palindrome (8314450544138).
The spelling of 1302330212107 in words is "one trillion, three hundred two billion, three hundred thirty million, two hundred twelve thousand, one hundred seven".
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