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13023321433 = 31661635563
BaseRepresentation
bin11000010000100000…
…00001110101011001
31020121121200021110021
430020100001311121
5203132432241213
65552142550441
7640505256103
oct141020016531
936547607407
1013023321433
115583364171
122635598421
1312c7178b75
148b78ba573
1551350bd8d
hex308401d59

13023321433 has 8 divisors (see below), whose sum is σ = 13463787776. Its totient is φ = 12584127600.

The previous prime is 13023321407. The next prime is 13023321481. The reversal of 13023321433 is 33412332031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13023321433 - 25 = 13023321401 is a prime.

It is a super-2 number, since 2×130233214332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13023321398 and 13023321407.

It is not an unprimeable number, because it can be changed into a prime (13023321403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 297291 + ... + 338272.

It is an arithmetic number, because the mean of its divisors is an integer number (1682973472).

Almost surely, 213023321433 is an apocalyptic number.

It is an amenable number.

13023321433 is a deficient number, since it is larger than the sum of its proper divisors (440466343).

13023321433 is an equidigital number, since it uses as much as digits as its factorization.

13023321433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 636255.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 13023321433 its reverse (33412332031), we get a palindrome (46435653464).

The spelling of 13023321433 in words is "thirteen billion, twenty-three million, three hundred twenty-one thousand, four hundred thirty-three".

Divisors: 1 31 661 20491 635563 19702453 420107143 13023321433