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13023335445 = 353152353551
BaseRepresentation
bin11000010000100000…
…00101010000010101
31020121121200222200020
430020100011100111
5203132433213240
65552143135353
7640505345001
oct141020052025
936547628606
1013023335445
11558337374a
1226355a4559
1312c7182363
148b78c1701
155135110d0
hex308405415

13023335445 has 32 divisors (see below), whose sum is σ = 21551038464. Its totient is φ = 6708744000.

The previous prime is 13023335419. The next prime is 13023335477. The reversal of 13023335445 is 54453332031.

It is not a de Polignac number, because 13023335445 - 27 = 13023335317 is a prime.

It is a super-2 number, since 2×130233354452 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 216420 + ... + 269970.

It is an arithmetic number, because the mean of its divisors is an integer number (673469952).

Almost surely, 213023335445 is an apocalyptic number.

13023335445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13023335445 is a deficient number, since it is larger than the sum of its proper divisors (8527703019).

13023335445 is a wasteful number, since it uses less digits than its factorization.

13023335445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54113.

The product of its (nonzero) digits is 64800, while the sum is 33.

Adding to 13023335445 its reverse (54453332031), we get a palindrome (67476667476).

The spelling of 13023335445 in words is "thirteen billion, twenty-three million, three hundred thirty-five thousand, four hundred forty-five".

Divisors: 1 3 5 15 31 93 155 465 523 1569 2615 7845 16213 48639 53551 81065 160653 243195 267755 803265 1660081 4980243 8300405 24901215 28007173 84021519 140035865 420107595 868222363 2604667089 4341111815 13023335445