Base | Representation |
---|---|
bin | 11101100111001001111101… |
… | …100010000110100110000111 |
3 | 122002010020222122211002111221 |
4 | 131213021331202012212013 |
5 | 114032223421214104343 |
6 | 1140552415512341211 |
7 | 36301050341501326 |
oct | 3547117542064607 |
9 | 562106878732457 |
10 | 130234104441223 |
11 | 38550a78840942 |
12 | 127342aa0a4807 |
13 | 578903c3c7ca3 |
14 | 24235158680bd |
15 | 100ca4bb4c5ed |
hex | 76727d886987 |
130234104441223 has 2 divisors, whose sum is σ = 130234104441224. Its totient is φ = 130234104441222.
The previous prime is 130234104441211. The next prime is 130234104441229. The reversal of 130234104441223 is 322144401432031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130234104441223 - 245 = 95049732352391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130234104441229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65117052220611 + 65117052220612.
It is an arithmetic number, because the mean of its divisors is an integer number (65117052220612).
Almost surely, 2130234104441223 is an apocalyptic number.
130234104441223 is a deficient number, since it is larger than the sum of its proper divisors (1).
130234104441223 is an equidigital number, since it uses as much as digits as its factorization.
130234104441223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 130234104441223 its reverse (322144401432031), we get a palindrome (452378505873254).
The spelling of 130234104441223 in words is "one hundred thirty trillion, two hundred thirty-four billion, one hundred four million, four hundred forty-one thousand, two hundred twenty-three".
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