Base | Representation |
---|---|
bin | 11101100111001010000101… |
… | …001000100110000110100011 |
3 | 122002010021022112210100012122 |
4 | 131213022011020212012203 |
5 | 114032224201341103014 |
6 | 1140552440310014455 |
7 | 36301053450500042 |
oct | 3547120510460643 |
9 | 562107275710178 |
10 | 130234231972259 |
11 | 38551033826898 |
12 | 1273432494742b |
13 | 578905c95aa3c |
14 | 2423528784559 |
15 | 100ca57e3e58e |
hex | 7672852261a3 |
130234231972259 has 2 divisors, whose sum is σ = 130234231972260. Its totient is φ = 130234231972258.
The previous prime is 130234231972223. The next prime is 130234231972261. The reversal of 130234231972259 is 952279132432031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130234231972259 - 28 = 130234231972003 is a prime.
Together with 130234231972261, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130234231972259.
It is not a weakly prime, because it can be changed into another prime (130234231972219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65117115986129 + 65117115986130.
It is an arithmetic number, because the mean of its divisors is an integer number (65117115986130).
Almost surely, 2130234231972259 is an apocalyptic number.
130234231972259 is a deficient number, since it is larger than the sum of its proper divisors (1).
130234231972259 is an equidigital number, since it uses as much as digits as its factorization.
130234231972259 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4898880, while the sum is 53.
The spelling of 130234231972259 in words is "one hundred thirty trillion, two hundred thirty-four billion, two hundred thirty-one million, nine hundred seventy-two thousand, two hundred fifty-nine".
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