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130234231972259 is a prime number
BaseRepresentation
bin11101100111001010000101…
…001000100110000110100011
3122002010021022112210100012122
4131213022011020212012203
5114032224201341103014
61140552440310014455
736301053450500042
oct3547120510460643
9562107275710178
10130234231972259
1138551033826898
121273432494742b
13578905c95aa3c
142423528784559
15100ca57e3e58e
hex7672852261a3

130234231972259 has 2 divisors, whose sum is σ = 130234231972260. Its totient is φ = 130234231972258.

The previous prime is 130234231972223. The next prime is 130234231972261. The reversal of 130234231972259 is 952279132432031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130234231972259 - 28 = 130234231972003 is a prime.

Together with 130234231972261, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130234231972259.

It is not a weakly prime, because it can be changed into another prime (130234231972219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65117115986129 + 65117115986130.

It is an arithmetic number, because the mean of its divisors is an integer number (65117115986130).

Almost surely, 2130234231972259 is an apocalyptic number.

130234231972259 is a deficient number, since it is larger than the sum of its proper divisors (1).

130234231972259 is an equidigital number, since it uses as much as digits as its factorization.

130234231972259 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4898880, while the sum is 53.

The spelling of 130234231972259 in words is "one hundred thirty trillion, two hundred thirty-four billion, two hundred thirty-one million, nine hundred seventy-two thousand, two hundred fifty-nine".