Base | Representation |
---|---|
bin | 10010111100111010001… |
… | …111000010110111100010 |
3 | 11121111121011021011211222 |
4 | 102330322033002313202 |
5 | 132314204120104442 |
6 | 2434143045335042 |
7 | 163043333211134 |
oct | 22747217026742 |
9 | 4544534234758 |
10 | 1302352113122 |
11 | 4623628a7635 |
12 | 1904a3107482 |
13 | 95a714b7758 |
14 | 47069b01054 |
15 | 23d2568c8d2 |
hex | 12f3a3c2de2 |
1302352113122 has 4 divisors (see below), whose sum is σ = 1953528169686. Its totient is φ = 651176056560.
The previous prime is 1302352113113. The next prime is 1302352113131. The reversal of 1302352113122 is 2213112532031.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (1302352113113) and next prime (1302352113131).
It can be written as a sum of positive squares in only one way, i.e., 866330931361 + 436021181761 = 930769^2 + 660319^2 .
It is a super-2 number, since 2×13023521131222 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1302352113091 and 1302352113100.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325588028279 + ... + 325588028282.
Almost surely, 21302352113122 is an apocalyptic number.
1302352113122 is a deficient number, since it is larger than the sum of its proper divisors (651176056564).
1302352113122 is an equidigital number, since it uses as much as digits as its factorization.
1302352113122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 651176056563.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 1302352113122 its reverse (2213112532031), we get a palindrome (3515464645153).
The spelling of 1302352113122 in words is "one trillion, three hundred two billion, three hundred fifty-two million, one hundred thirteen thousand, one hundred twenty-two".
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