130235422121017 has 4 divisors (see below), whose sum is σ = 133755298394596. Its totient is φ = 126715545847440.

The previous prime is 130235422121003. The next prime is 130235422121039. The reversal of 130235422121017 is 710121224532031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 125300733075961 + 4934689045056 = 11193781^2 + 2221416^2 .

It is a cyclic number.

It is not a de Polignac number, because 130235422121017 - 2¹⁵ = 130235422088249 is a prime.

It is a super-3 number, since 3×130235422121017³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130235422121617) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1759938136734 + ... + 1759938136807.

It is an arithmetic number, because the mean of its divisors is an integer number (33438824598649).

Almost surely, 2^{130235422121017} is an apocalyptic number.

It is an amenable number.

130235422121017 is a deficient number, since it is larger than the sum of its proper divisors (3519876273579).

130235422121017 is an equidigital number, since it uses as much as digits as its factorization.

130235422121017 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3519876273578.

The product of its (nonzero) digits is 20160, while the sum is 34.

Adding to 130235422121017 its reverse (710121224532031), we get a palindrome (840356646653048).

The spelling of 130235422121017 in words is "one hundred thirty trillion, two hundred thirty-five billion, four hundred twenty-two million, one hundred twenty-one thousand, seventeen".