Base | Representation |
---|---|
bin | 111100101001011101… |
… | …0100100011100100111 |
3 | 110110011122201210201010 |
4 | 1321102322210130213 |
5 | 4113212431313411 |
6 | 135455333233303 |
7 | 12260320422456 |
oct | 1712272443447 |
9 | 413148653633 |
10 | 130240104231 |
11 | 50264163a86 |
12 | 212a9192833 |
13 | c387860c43 |
14 | 643732ab9d |
15 | 35c3e907a6 |
hex | 1e52ea4727 |
130240104231 has 4 divisors (see below), whose sum is σ = 173653472312. Its totient is φ = 86826736152.
The previous prime is 130240104227. The next prime is 130240104263. The reversal of 130240104231 is 132401042031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 130240104231 - 22 = 130240104227 is a prime.
It is a super-2 number, since 2×1302401042312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130240104198 and 130240104207.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130240105231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21706684036 + ... + 21706684041.
It is an arithmetic number, because the mean of its divisors is an integer number (43413368078).
Almost surely, 2130240104231 is an apocalyptic number.
130240104231 is a deficient number, since it is larger than the sum of its proper divisors (43413368081).
130240104231 is an equidigital number, since it uses as much as digits as its factorization.
130240104231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43413368080.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 130240104231 its reverse (132401042031), we get a palindrome (262641146262).
The spelling of 130240104231 in words is "one hundred thirty billion, two hundred forty million, one hundred four thousand, two hundred thirty-one".
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