130240131140401 has 4 divisors (see below), whose sum is σ = 132074499184704. Its totient is φ = 128405763096100.

The previous prime is 130240131140369. The next prime is 130240131140417. The reversal of 130240131140401 is 104041131042031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130240131140401 - 2⁵ = 130240131140369 is a prime.

It is a super-4 number, since 4×130240131140401⁴ (a number of 58 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130240131140491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 917184022045 + ... + 917184022186.

It is an arithmetic number, because the mean of its divisors is an integer number (33018624796176).

Almost surely, 2^{130240131140401} is an apocalyptic number.

It is an amenable number.

130240131140401 is a deficient number, since it is larger than the sum of its proper divisors (1834368044303).

130240131140401 is an equidigital number, since it uses as much as digits as its factorization.

130240131140401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1834368044302.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 130240131140401 its reverse (104041131042031), we get a palindrome (234281262182432).

The spelling of 130240131140401 in words is "one hundred thirty trillion, two hundred forty billion, one hundred thirty-one million, one hundred forty thousand, four hundred one".