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13024117 is a prime number
BaseRepresentation
bin110001101011…
…101101110101
3220111200201201
4301223231311
511313232432
61143052501
7215463121
oct61535565
926450651
1013024117
117396237
124441131
1329101a2
141a30581
151223ee7
hexc6bb75

13024117 has 2 divisors, whose sum is σ = 13024118. Its totient is φ = 13024116.

The previous prime is 13024087. The next prime is 13024129. The reversal of 13024117 is 71142031.

13024117 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12680721 + 343396 = 3561^2 + 586^2 .

It is a cyclic number.

It is not a de Polignac number, because 13024117 - 211 = 13022069 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13024094 and 13024103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13021117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6512058 + 6512059.

It is an arithmetic number, because the mean of its divisors is an integer number (6512059).

Almost surely, 213024117 is an apocalyptic number.

It is an amenable number.

13024117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13024117 is an equidigital number, since it uses as much as digits as its factorization.

13024117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 19.

The square root of 13024117 is about 3608.8941519529. The cubic root of 13024117 is about 235.2787818694.

Adding to 13024117 its reverse (71142031), we get a palindrome (84166148).

The spelling of 13024117 in words is "thirteen million, twenty-four thousand, one hundred seventeen".