Base | Representation |
---|---|
bin | 111100101001100000… |
… | …1111111011111110111 |
3 | 110110011210101122212002 |
4 | 1321103001333133313 |
5 | 4113213431100124 |
6 | 135455443045515 |
7 | 12260343105413 |
oct | 1712301773767 |
9 | 413153348762 |
10 | 130242050039 |
11 | 50265272992 |
12 | 212a997089b |
13 | c3880927ca |
14 | 64376b5d43 |
15 | 35c42270ae |
hex | 1e5307f7f7 |
130242050039 has 2 divisors, whose sum is σ = 130242050040. Its totient is φ = 130242050038.
The previous prime is 130242050023. The next prime is 130242050077. The reversal of 130242050039 is 930050242031.
It is a weak prime.
It is an emirp because it is prime and its reverse (930050242031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130242050039 - 24 = 130242050023 is a prime.
It is a super-2 number, since 2×1302420500392 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130242049993 and 130242050020.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130242050089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65121025019 + 65121025020.
It is an arithmetic number, because the mean of its divisors is an integer number (65121025020).
Almost surely, 2130242050039 is an apocalyptic number.
130242050039 is a deficient number, since it is larger than the sum of its proper divisors (1).
130242050039 is an equidigital number, since it uses as much as digits as its factorization.
130242050039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 29.
The spelling of 130242050039 in words is "one hundred thirty billion, two hundred forty-two million, fifty thousand, thirty-nine".
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