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1302423313101 = 3434141104367
BaseRepresentation
bin10010111100111110011…
…110101001101011001101
311121111210010020111212020
4102330332132221223031
5132314330332004401
62434154111400353
7163045156333221
oct22747636515315
94544703214766
101302423313101
1146239a008199
12190502b230b9
1395a83186511
1447075356781
1523d2ba53d36
hex12f3e7a9acd

1302423313101 has 4 divisors (see below), whose sum is σ = 1736564417472. Its totient is φ = 868282208732.

The previous prime is 1302423313063. The next prime is 1302423313117. The reversal of 1302423313101 is 1013133242031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1302423313101 - 217 = 1302423182029 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1302423413101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217070552181 + ... + 217070552186.

It is an arithmetic number, because the mean of its divisors is an integer number (434141104368).

Almost surely, 21302423313101 is an apocalyptic number.

It is an amenable number.

1302423313101 is a deficient number, since it is larger than the sum of its proper divisors (434141104371).

1302423313101 is an equidigital number, since it uses as much as digits as its factorization.

1302423313101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 434141104370.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 1302423313101 its reverse (1013133242031), we get a palindrome (2315556555132).

The spelling of 1302423313101 in words is "one trillion, three hundred two billion, four hundred twenty-three million, three hundred thirteen thousand, one hundred one".

Divisors: 1 3 434141104367 1302423313101