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1302428137 is a prime number
BaseRepresentation
bin100110110100001…
…0111100111101001
310100202202012112011
41031220113213221
510131410200022
6333123315521
744163312403
oct11550274751
93322665464
101302428137
1160920659a
1230421bba1
13179aa824a
14c4d93b73
157951e977
hex4da179e9

1302428137 has 2 divisors, whose sum is σ = 1302428138. Its totient is φ = 1302428136.

The previous prime is 1302428119. The next prime is 1302428147. The reversal of 1302428137 is 7318242031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1114491456 + 187936681 = 33384^2 + 13709^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1302428137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1302428099 and 1302428108.

It is not a weakly prime, because it can be changed into another prime (1302428147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651214068 + 651214069.

It is an arithmetic number, because the mean of its divisors is an integer number (651214069).

Almost surely, 21302428137 is an apocalyptic number.

It is an amenable number.

1302428137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302428137 is an equidigital number, since it uses as much as digits as its factorization.

1302428137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 31.

The square root of 1302428137 is about 36089.1692478505. The cubic root of 1302428137 is about 1092.0719608126.

The spelling of 1302428137 in words is "one billion, three hundred two million, four hundred twenty-eight thousand, one hundred thirty-seven".