Base | Representation |
---|---|
bin | 1011110110000111010011… |
… | …0110101110001001001111 |
3 | 1201010002222221202200021202 |
4 | 2331201310312232021033 |
5 | 3201342232120441221 |
6 | 43411140442420115 |
7 | 2512655220534656 |
oct | 275416466561117 |
9 | 51102887680252 |
10 | 13024301343311 |
11 | 41716366246a5 |
12 | 156424420163b |
13 | 736256532abb |
14 | 3305456a419d |
15 | 178bd2d4ed0b |
hex | bd874dae24f |
13024301343311 has 2 divisors, whose sum is σ = 13024301343312. Its totient is φ = 13024301343310.
The previous prime is 13024301343233. The next prime is 13024301343371. The reversal of 13024301343311 is 11334310342031.
It is a strong prime.
It is an emirp because it is prime and its reverse (11334310342031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13024301343311 - 222 = 13024297149007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13024301343371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6512150671655 + 6512150671656.
It is an arithmetic number, because the mean of its divisors is an integer number (6512150671656).
Almost surely, 213024301343311 is an apocalyptic number.
13024301343311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13024301343311 is an equidigital number, since it uses as much as digits as its factorization.
13024301343311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 13024301343311 its reverse (11334310342031), we get a palindrome (24358611685342).
The spelling of 13024301343311 in words is "thirteen trillion, twenty-four billion, three hundred one million, three hundred forty-three thousand, three hundred eleven".
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