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1302432220034 = 2111716321364657
BaseRepresentation
bin10010111100111111000…
…000101000001110000010
311121111210202000000212122
4102330333000220032002
5132314340122020114
62434155030324242
7163045325131031
oct22747700501602
94544722000778
101302432220034
114623a40410a0
12190505ab9682
1395a84c846aa
14470765d4718
1523d2c712e8e
hex12f3f028382

1302432220034 has 32 divisors (see below), whose sum is σ = 2270464934976. Its totient is φ = 553771883520.

The previous prime is 1302432219989. The next prime is 1302432220087. The reversal of 1302432220034 is 4300222342031.

It is a super-2 number, since 2×13024322200342 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1302432219985 and 1302432220012.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10621367 + ... + 10743290.

It is an arithmetic number, because the mean of its divisors is an integer number (70952029218).

Almost surely, 21302432220034 is an apocalyptic number.

1302432220034 is a deficient number, since it is larger than the sum of its proper divisors (968032714942).

1302432220034 is a wasteful number, since it uses less digits than its factorization.

1302432220034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21364850.

The product of its (nonzero) digits is 6912, while the sum is 26.

Adding to 1302432220034 its reverse (4300222342031), we get a palindrome (5602654562065).

The spelling of 1302432220034 in words is "one trillion, three hundred two billion, four hundred thirty-two million, two hundred twenty thousand, thirty-four".

Divisors: 1 2 11 17 22 34 163 187 326 374 1793 2771 3586 5542 30481 60962 21364657 42729314 235011227 363199169 470022454 726398338 3482439091 3995190859 6964878182 7990381718 38306830001 59201464547 76613660002 118402929094 651216110017 1302432220034