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130244112301097 is a prime number
BaseRepresentation
bin11101100111010011010010…
…000011000011110000101001
3122002011012211010101001100202
4131213103102003003300221
5114032404420222113342
61141001152535441545
736301553343060344
oct3547232203036051
9562135733331322
10130244112301097
1138555243a34113
12127362218262b5
135789c75907b72
142423bc4a7545b
15100ce3555e332
hex7674d20c3c29

130244112301097 has 2 divisors, whose sum is σ = 130244112301098. Its totient is φ = 130244112301096.

The previous prime is 130244112301031. The next prime is 130244112301139. The reversal of 130244112301097 is 790103211442031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122216319412201 + 8027792888896 = 11055149^2 + 2833336^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130244112301097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130244112301097.

It is not a weakly prime, because it can be changed into another prime (130244112301997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65122056150548 + 65122056150549.

It is an arithmetic number, because the mean of its divisors is an integer number (65122056150549).

Almost surely, 2130244112301097 is an apocalyptic number.

It is an amenable number.

130244112301097 is a deficient number, since it is larger than the sum of its proper divisors (1).

130244112301097 is an equidigital number, since it uses as much as digits as its factorization.

130244112301097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 38.

The spelling of 130244112301097 in words is "one hundred thirty trillion, two hundred forty-four billion, one hundred twelve million, three hundred one thousand, ninety-seven".