Base | Representation |
---|---|
bin | 111100101001100101… |
… | …0100101110010010111 |
3 | 110110011221122011201222 |
4 | 1321103022211302113 |
5 | 4113220020212043 |
6 | 135500003240555 |
7 | 12260401213661 |
oct | 1712312456227 |
9 | 413157564658 |
10 | 130244304023 |
11 | 50266572389 |
12 | 212aa67915b |
13 | c3886a1722 |
14 | 6437b01531 |
15 | 35c451ed68 |
hex | 1e532a5c97 |
130244304023 has 2 divisors, whose sum is σ = 130244304024. Its totient is φ = 130244304022.
The previous prime is 130244304019. The next prime is 130244304103. The reversal of 130244304023 is 320403442031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130244304023 - 22 = 130244304019 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 130244303983 and 130244304001.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130244394023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65122152011 + 65122152012.
It is an arithmetic number, because the mean of its divisors is an integer number (65122152012).
Almost surely, 2130244304023 is an apocalyptic number.
130244304023 is a deficient number, since it is larger than the sum of its proper divisors (1).
130244304023 is an equidigital number, since it uses as much as digits as its factorization.
130244304023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 130244304023 its reverse (320403442031), we get a palindrome (450647746054).
The spelling of 130244304023 in words is "one hundred thirty billion, two hundred forty-four million, three hundred four thousand, twenty-three".
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