Base | Representation |
---|---|
bin | 111100101001101000… |
… | …1110111001000000011 |
3 | 110110012002020000022121 |
4 | 1321103101313020003 |
5 | 4113221012210201 |
6 | 135500112145111 |
7 | 12260423342626 |
oct | 1712321671003 |
9 | 413162200277 |
10 | 130246210051 |
11 | 50267654411 |
12 | 212ab238197 |
13 | c388bbb159 |
14 | 6438079dbd |
15 | 35c47999a1 |
hex | 1e53477203 |
130246210051 has 4 divisors (see below), whose sum is σ = 130507225000. Its totient is φ = 129985195104.
The previous prime is 130246210027. The next prime is 130246210079. The reversal of 130246210051 is 150012642031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130246210051 - 25 = 130246210019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130246209998 and 130246210025.
It is not an unprimeable number, because it can be changed into a prime (130246210021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130506726 + ... + 130507723.
It is an arithmetic number, because the mean of its divisors is an integer number (32626806250).
Almost surely, 2130246210051 is an apocalyptic number.
130246210051 is a deficient number, since it is larger than the sum of its proper divisors (261014949).
130246210051 is an equidigital number, since it uses as much as digits as its factorization.
130246210051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 261014948.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 130246210051 its reverse (150012642031), we get a palindrome (280258852082).
The spelling of 130246210051 in words is "one hundred thirty billion, two hundred forty-six million, two hundred ten thousand, fifty-one".
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