Base | Representation |
---|---|
bin | 11000010000101110… |
… | …00001110100111101 |
3 | 1020121202010111120111 |
4 | 30020113001310331 |
5 | 203133420001123 |
6 | 5552250150021 |
7 | 640530000643 |
oct | 141027016475 |
9 | 36552114514 |
10 | 13025156413 |
11 | 55843a7885 |
12 | 2636122311 |
13 | 12c766c159 |
14 | 8b7c37193 |
15 | 51377090d |
hex | 3085c1d3d |
13025156413 has 2 divisors, whose sum is σ = 13025156414. Its totient is φ = 13025156412.
The previous prime is 13025156383. The next prime is 13025156461. The reversal of 13025156413 is 31465152031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11898010084 + 1127146329 = 109078^2 + 33573^2 .
It is an emirp because it is prime and its reverse (31465152031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13025156413 - 217 = 13025025341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13025136413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6512578206 + 6512578207.
It is an arithmetic number, because the mean of its divisors is an integer number (6512578207).
Almost surely, 213025156413 is an apocalyptic number.
It is an amenable number.
13025156413 is a deficient number, since it is larger than the sum of its proper divisors (1).
13025156413 is an equidigital number, since it uses as much as digits as its factorization.
13025156413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
The spelling of 13025156413 in words is "thirteen billion, twenty-five million, one hundred fifty-six thousand, four hundred thirteen".
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