Base | Representation |
---|---|
bin | 1011110110001011100100… |
… | …0111010010100010111111 |
3 | 1201010012221202122120020220 |
4 | 2331202321013102202333 |
5 | 3201402103303144112 |
6 | 43411450232112423 |
7 | 2513025464531163 |
oct | 275427107224277 |
9 | 51105852576226 |
10 | 13025446537407 |
11 | 4172073aa79a7 |
12 | 1564503835713 |
13 | 7363a9878545 |
14 | 330613808ca3 |
15 | 178c4d66198c |
hex | bd8b91d28bf |
13025446537407 has 4 divisors (see below), whose sum is σ = 17367262049880. Its totient is φ = 8683631024936.
The previous prime is 13025446537393. The next prime is 13025446537423. The reversal of 13025446537407 is 70473564452031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13025446537407 - 212 = 13025446533311 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13025446537407.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13025446537507) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2170907756232 + ... + 2170907756237.
It is an arithmetic number, because the mean of its divisors is an integer number (4341815512470).
Almost surely, 213025446537407 is an apocalyptic number.
13025446537407 is a deficient number, since it is larger than the sum of its proper divisors (4341815512473).
13025446537407 is an equidigital number, since it uses as much as digits as its factorization.
13025446537407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4341815512472.
The product of its (nonzero) digits is 8467200, while the sum is 51.
The spelling of 13025446537407 in words is "thirteen trillion, twenty-five billion, four hundred forty-six million, five hundred thirty-seven thousand, four hundred seven".
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