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13026549138423 = 34342183046141
BaseRepresentation
bin1011110110001111101011…
…0101011000001111110111
31201010022210121101111111120
42331203322311120033313
53201411333034412143
643412151500435023
72513065013506332
oct275437265301767
951108717344446
1013026549138423
11417258a429407
121564770b48a73
1373652412a092
143306ba023619
15178cb535d383
hexbd8fad583f7

13026549138423 has 4 divisors (see below), whose sum is σ = 17368732184568. Its totient is φ = 8684366092280.

The previous prime is 13026549138403. The next prime is 13026549138437. The reversal of 13026549138423 is 32483194562031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13026549138423 - 214 = 13026549122039 is a prime.

It is a super-2 number, since 2×130265491384232 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13026549138403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2171091523068 + ... + 2171091523073.

It is an arithmetic number, because the mean of its divisors is an integer number (4342183046142).

Almost surely, 213026549138423 is an apocalyptic number.

13026549138423 is a deficient number, since it is larger than the sum of its proper divisors (4342183046145).

13026549138423 is an equidigital number, since it uses as much as digits as its factorization.

13026549138423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4342183046144.

The product of its (nonzero) digits is 3732480, while the sum is 51.

The spelling of 13026549138423 in words is "thirteen trillion, twenty-six billion, five hundred forty-nine million, one hundred thirty-eight thousand, four hundred twenty-three".

Divisors: 1 3 4342183046141 13026549138423