13028747590963 has 4 divisors (see below), whose sum is σ = 14030958944128. Its totient is φ = 12026536237800.

The previous prime is 13028747590933. The next prime is 13028747591009. The reversal of 13028747590963 is 36909574782031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13028747590963 - 2⁵ = 13028747590931 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13028747590895 and 13028747590904.

It is not an unprimeable number, because it can be changed into a prime (13028747590933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501105676563 + ... + 501105676588.

It is an arithmetic number, because the mean of its divisors is an integer number (3507739736032).

It is a 1-persistent number, because it is pandigital, but 2⋅13028747590963 = 26057495181926 is not.

Almost surely, 2^{13028747590963} is an apocalyptic number.

13028747590963 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13028747590963 is a deficient number, since it is larger than the sum of its proper divisors (1002211353165).

13028747590963 is a wasteful number, since it uses less digits than its factorization.

13028747590963 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1002211353164.

The product of its (nonzero) digits is 68584320, while the sum is 64.

The spelling of 13028747590963 in words is "thirteen trillion, twenty-eight billion, seven hundred forty-seven million, five hundred ninety thousand, nine hundred sixty-three".