Base | Representation |
---|---|
bin | 10010111101100000110… |
… | …111101110110110010000 |
3 | 11121120021022222011020110 |
4 | 102331200313232312100 |
5 | 132322021040010412 |
6 | 2434331242441320 |
7 | 163065363630312 |
oct | 22754067566620 |
9 | 4546238864213 |
10 | 1303000313232 |
11 | 462665786a02 |
12 | 190644203240 |
13 | 95b4588b407 |
14 | 470cbc337b2 |
15 | 23d6252bd3c |
hex | 12f60deed90 |
1303000313232 has 40 divisors (see below), whose sum is σ = 3367065076384. Its totient is φ = 434206865664.
The previous prime is 1303000313191. The next prime is 1303000313243. The reversal of 1303000313232 is 2323130003031.
It is a super-2 number, since 2×13030003132322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1303000313199 and 1303000313208.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3788878 + ... + 4118445.
Almost surely, 21303000313232 is an apocalyptic number.
1303000313232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1303000313232 is an abundant number, since it is smaller than the sum of its proper divisors (2064064763152).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1303000313232 is a wasteful number, since it uses less digits than its factorization.
1303000313232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7910767 (or 7910761 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 21.
Adding to 1303000313232 its reverse (2323130003031), we get a palindrome (3626130316263).
The spelling of 1303000313232 in words is "one trillion, three hundred three billion, three hundred thirteen thousand, two hundred thirty-two".
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