Base | Representation |
---|---|
bin | 1011110110011101110001… |
… | …0100101100001000100101 |
3 | 1201010200120020220221201212 |
4 | 2331213130110230020211 |
5 | 3201442110022014231 |
6 | 43414015121201205 |
7 | 2513260531252451 |
oct | 275473424541045 |
9 | 51120506827655 |
10 | 13030332219941 |
11 | 4174150924563 |
12 | 1565447a90205 |
13 | 7369a7b1c85a |
14 | 33095862d661 |
15 | 178e3753642b |
hex | bd9dc52c225 |
13030332219941 has 2 divisors, whose sum is σ = 13030332219942. Its totient is φ = 13030332219940.
The previous prime is 13030332219929. The next prime is 13030332220043. The reversal of 13030332219941 is 14991223303031.
13030332219941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13029139968100 + 1192251841 = 3609590^2 + 34529^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13030332219941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13030332219341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515166109970 + 6515166109971.
It is an arithmetic number, because the mean of its divisors is an integer number (6515166109971).
Almost surely, 213030332219941 is an apocalyptic number.
It is an amenable number.
13030332219941 is a deficient number, since it is larger than the sum of its proper divisors (1).
13030332219941 is an equidigital number, since it uses as much as digits as its factorization.
13030332219941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 104976, while the sum is 41.
The spelling of 13030332219941 in words is "thirteen trillion, thirty billion, three hundred thirty-two million, two hundred nineteen thousand, nine hundred forty-one".
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