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130305152437 is a prime number
BaseRepresentation
bin111100101011011001…
…0101101010110110101
3110110100012010121001221
41321112302231112311
54113331104334222
6135510015350341
712262040343415
oct1712662552665
9413305117057
10130305152437
1150297952729
1221306b223b1
13c3981878c5
146441c20645
1535c9a3e0c7
hex1e56cad5b5

130305152437 has 2 divisors, whose sum is σ = 130305152438. Its totient is φ = 130305152436.

The previous prime is 130305152387. The next prime is 130305152443. The reversal of 130305152437 is 734251503031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118037596356 + 12267556081 = 343566^2 + 110759^2 .

It is a cyclic number.

It is not a de Polignac number, because 130305152437 - 223 = 130296763829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130305162437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65152576218 + 65152576219.

It is an arithmetic number, because the mean of its divisors is an integer number (65152576219).

Almost surely, 2130305152437 is an apocalyptic number.

It is an amenable number.

130305152437 is a deficient number, since it is larger than the sum of its proper divisors (1).

130305152437 is an equidigital number, since it uses as much as digits as its factorization.

130305152437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 37800, while the sum is 34.

Adding to 130305152437 its reverse (734251503031), we get a palindrome (864556655468).

The spelling of 130305152437 in words is "one hundred thirty billion, three hundred five million, one hundred fifty-two thousand, four hundred thirty-seven".