1303100011303 has 4 divisors (see below), whose sum is σ = 1303102590928. Its totient is φ = 1303097431680.

The previous prime is 1303100011289. The next prime is 1303100011309. The reversal of 1303100011303 is 3031100013031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1303100011303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1303100011309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255738 + ... + 1634503.

It is an arithmetic number, because the mean of its divisors is an integer number (325775647732).

Almost surely, 2^{1303100011303} is an apocalyptic number.

1303100011303 is a deficient number, since it is larger than the sum of its proper divisors (2579625).

1303100011303 is an equidigital number, since it uses as much as digits as its factorization.

1303100011303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2579624.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 1303100011303 its reverse (3031100013031), we get a palindrome (4334200024334).

The spelling of 1303100011303 in words is "one trillion, three hundred three billion, one hundred million, eleven thousand, three hundred three".