Base | Representation |
---|---|
bin | 10010111101100110111… |
… | …011101000101111100011 |
3 | 11121120112102022101101201 |
4 | 102331212323220233203 |
5 | 132322223103000344 |
6 | 2434345314142031 |
7 | 163101040146424 |
oct | 22754673505743 |
9 | 4546472271351 |
10 | 1303102000099 |
11 | 46270811a839 |
12 | 190672281917 |
13 | 95b60972963 |
14 | 470db54364b |
15 | 23d6b4164d4 |
hex | 12f66ee8be3 |
1303102000099 has 2 divisors, whose sum is σ = 1303102000100. Its totient is φ = 1303102000098.
The previous prime is 1303102000069. The next prime is 1303102000129. The reversal of 1303102000099 is 9900002013031.
It is a balanced prime because it is at equal distance from previous prime (1303102000069) and next prime (1303102000129).
It is a cyclic number.
It is not a de Polignac number, because 1303102000099 - 213 = 1303101991907 is a prime.
It is not a weakly prime, because it can be changed into another prime (1303102000069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651551000049 + 651551000050.
It is an arithmetic number, because the mean of its divisors is an integer number (651551000050).
Almost surely, 21303102000099 is an apocalyptic number.
1303102000099 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303102000099 is an equidigital number, since it uses as much as digits as its factorization.
1303102000099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 28.
The spelling of 1303102000099 in words is "one trillion, three hundred three billion, one hundred two million, ninety-nine", and thus it is an aban number.
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