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130310211301 is a prime number
BaseRepresentation
bin111100101011100011…
…0000000011011100101
3110110100112122121112021
41321113012000123211
54113333403230201
6135510320023141
712262131343324
oct1712706003345
9413315577467
10130310211301
115029a798506
1221308761ab1
13c39923940a
14644277a0bb
1535ca1dcea1
hex1e571806e5

130310211301 has 2 divisors, whose sum is σ = 130310211302. Its totient is φ = 130310211300.

The previous prime is 130310211281. The next prime is 130310211313. The reversal of 130310211301 is 103112013031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127787660676 + 2522550625 = 357474^2 + 50225^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130310211301 is a prime.

It is a super-2 number, since 2×1303102113012 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130310211341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65155105650 + 65155105651.

It is an arithmetic number, because the mean of its divisors is an integer number (65155105651).

Almost surely, 2130310211301 is an apocalyptic number.

It is an amenable number.

130310211301 is a deficient number, since it is larger than the sum of its proper divisors (1).

130310211301 is an equidigital number, since it uses as much as digits as its factorization.

130310211301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 130310211301 its reverse (103112013031), we get a palindrome (233422224332).

The spelling of 130310211301 in words is "one hundred thirty billion, three hundred ten million, two hundred eleven thousand, three hundred one".