Base | Representation |
---|---|
bin | 111100101011100011… |
… | …0011001100100111111 |
3 | 110110100112211211211011 |
4 | 1321113012121210333 |
5 | 4113333420024203 |
6 | 135510322140051 |
7 | 12262132252531 |
oct | 1712706314477 |
9 | 413315754734 |
10 | 130310314303 |
11 | 5029a858934 |
12 | 213087b1627 |
13 | c399274270 |
14 | 64427a5851 |
15 | 35ca20d76d |
hex | 1e5719993f |
130310314303 has 32 divisors (see below), whose sum is σ = 142541429184. Its totient is φ = 118414420992.
The previous prime is 130310314283. The next prime is 130310314307. The reversal of 130310314303 is 303413013031.
It is a cyclic number.
It is not a de Polignac number, because 130310314303 - 217 = 130310183231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130310314307) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 136736475 + ... + 136737427.
It is an arithmetic number, because the mean of its divisors is an integer number (4454419662).
Almost surely, 2130310314303 is an apocalyptic number.
130310314303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
130310314303 is a deficient number, since it is larger than the sum of its proper divisors (12231114881).
130310314303 is a wasteful number, since it uses less digits than its factorization.
130310314303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1675.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 130310314303 its reverse (303413013031), we get a palindrome (433723327334).
The spelling of 130310314303 in words is "one hundred thirty billion, three hundred ten million, three hundred fourteen thousand, three hundred three".
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