Search a number
-
+
130310329017997 is a prime number
BaseRepresentation
bin11101101000010000111100…
…110111110010011010001101
3122002101112201212210210111001
4131220100330313302122031
5114040001023212033442
61141051423321500301
736306416300634202
oct3550207467623215
9562345655723431
10130310329017997
1138580333602637
1212747021641691
1357932992bc05b
1424270a702bca9
15100ea0d9572b7
hex76843cdf268d

130310329017997 has 2 divisors, whose sum is σ = 130310329017998. Its totient is φ = 130310329017996.

The previous prime is 130310329017941. The next prime is 130310329018021. The reversal of 130310329017997 is 799710923013031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127281402992836 + 3028926025161 = 11281906^2 + 1740381^2 .

It is a cyclic number.

It is not a de Polignac number, because 130310329017997 - 211 = 130310329015949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130310329017907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65155164508998 + 65155164508999.

It is an arithmetic number, because the mean of its divisors is an integer number (65155164508999).

Almost surely, 2130310329017997 is an apocalyptic number.

It is an amenable number.

130310329017997 is a deficient number, since it is larger than the sum of its proper divisors (1).

130310329017997 is an equidigital number, since it uses as much as digits as its factorization.

130310329017997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1928934, while the sum is 55.

The spelling of 130310329017997 in words is "one hundred thirty trillion, three hundred ten billion, three hundred twenty-nine million, seventeen thousand, nine hundred ninety-seven".