Base | Representation |
---|---|
bin | 1011110110100001000010… |
… | …1101000000101110111011 |
3 | 1201010202211111112011102222 |
4 | 2331220100231000232323 |
5 | 3202000410004323003 |
6 | 43414242232514255 |
7 | 2513321361665513 |
oct | 275502055005673 |
9 | 51122744464388 |
10 | 13031211011003 |
11 | 4174561990269 |
12 | 156565224b98b |
13 | 736ab7bcb773 |
14 | 3309dd228843 |
15 | 178e89773c38 |
hex | bda10b40bbb |
13031211011003 has 2 divisors, whose sum is σ = 13031211011004. Its totient is φ = 13031211011002.
The previous prime is 13031211010999. The next prime is 13031211011011. The reversal of 13031211011003 is 30011011213031.
13031211011003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13031211011003 - 22 = 13031211010999 is a prime.
It is not a weakly prime, because it can be changed into another prime (13031211011303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515605505501 + 6515605505502.
It is an arithmetic number, because the mean of its divisors is an integer number (6515605505502).
Almost surely, 213031211011003 is an apocalyptic number.
13031211011003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13031211011003 is an equidigital number, since it uses as much as digits as its factorization.
13031211011003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 13031211011003 its reverse (30011011213031), we get a palindrome (43042222224034).
The spelling of 13031211011003 in words is "thirteen trillion, thirty-one billion, two hundred eleven million, eleven thousand, three".
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