Base | Representation |
---|---|
bin | 1011110110100001000010… |
… | …1101000000110001111111 |
3 | 1201010202211111112011201020 |
4 | 2331220100231000301333 |
5 | 3202000410004324244 |
6 | 43414242232515223 |
7 | 2513321361666213 |
oct | 275502055006177 |
9 | 51122744464636 |
10 | 13031211011199 |
11 | 4174561990427 |
12 | 156565224bb13 |
13 | 736ab7bcb894 |
14 | 3309dd228943 |
15 | 178e89773d19 |
hex | bda10b40c7f |
13031211011199 has 4 divisors (see below), whose sum is σ = 17374948014936. Its totient is φ = 8687474007464.
The previous prime is 13031211011197. The next prime is 13031211011233. The reversal of 13031211011199 is 99111011213031.
13031211011199 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13031211011199 - 21 = 13031211011197 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13031211011197) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2171868501864 + ... + 2171868501869.
It is an arithmetic number, because the mean of its divisors is an integer number (4343737003734).
Almost surely, 213031211011199 is an apocalyptic number.
13031211011199 is a deficient number, since it is larger than the sum of its proper divisors (4343737003737).
13031211011199 is an equidigital number, since it uses as much as digits as its factorization.
13031211011199 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4343737003736.
The product of its (nonzero) digits is 1458, while the sum is 33.
The spelling of 13031211011199 in words is "thirteen trillion, thirty-one billion, two hundred eleven million, eleven thousand, one hundred ninety-nine".
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