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13031211102137 is a prime number
BaseRepresentation
bin1011110110100001000010…
…1101010110111110111001
31201010202211111200210110022
42331220100231112332321
53202000410020232022
643414242234500225
72513321362525304
oct275502055267671
951122744623408
1013031211102137
114174561a42788
121565652294675
13736ab7c310a7
143309dd24db3b
15178e89790c42
hexbda10b56fb9

13031211102137 has 2 divisors, whose sum is σ = 13031211102138. Its totient is φ = 13031211102136.

The previous prime is 13031211102113. The next prime is 13031211102139. The reversal of 13031211102137 is 73120111213031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9757901527696 + 3273309574441 = 3123764^2 + 1809229^2 .

It is a cyclic number.

It is not a de Polignac number, because 13031211102137 - 236 = 12962491625401 is a prime.

Together with 13031211102139, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13031211102139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515605551068 + 6515605551069.

It is an arithmetic number, because the mean of its divisors is an integer number (6515605551069).

Almost surely, 213031211102137 is an apocalyptic number.

It is an amenable number.

13031211102137 is a deficient number, since it is larger than the sum of its proper divisors (1).

13031211102137 is an equidigital number, since it uses as much as digits as its factorization.

13031211102137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 26.

Adding to 13031211102137 its reverse (73120111213031), we get a palindrome (86151322315168).

The spelling of 13031211102137 in words is "thirteen trillion, thirty-one billion, two hundred eleven million, one hundred two thousand, one hundred thirty-seven".