Base | Representation |
---|---|
bin | 1011110110100001000011… |
… | …0100011110101111010111 |
3 | 1201010202211122012122012101 |
4 | 2331220100310132233113 |
5 | 3202000411010001134 |
6 | 43414242342502531 |
7 | 2513321414431645 |
oct | 275502064365727 |
9 | 51122748178171 |
10 | 13031212968919 |
11 | 4174562aa8282 |
12 | 1565652a34a47 |
13 | 736ab84359b2 |
14 | 3309dd5b8195 |
15 | 178e89a0de14 |
hex | bda10d1ebd7 |
13031212968919 has 2 divisors, whose sum is σ = 13031212968920. Its totient is φ = 13031212968918.
The previous prime is 13031212968913. The next prime is 13031212968973. The reversal of 13031212968919 is 91986921213031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13031212968919 - 25 = 13031212968887 is a prime.
It is a super-2 number, since 2×130312129689192 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13031212968919.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13031212968913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515606484459 + 6515606484460.
It is an arithmetic number, because the mean of its divisors is an integer number (6515606484460).
Almost surely, 213031212968919 is an apocalyptic number.
13031212968919 is a deficient number, since it is larger than the sum of its proper divisors (1).
13031212968919 is an equidigital number, since it uses as much as digits as its factorization.
13031212968919 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1259712, while the sum is 55.
The spelling of 13031212968919 in words is "thirteen trillion, thirty-one billion, two hundred twelve million, nine hundred sixty-eight thousand, nine hundred nineteen".
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