Base | Representation |
---|---|
bin | 11000010001011100… |
… | …01000110000111011 |
3 | 1020122011112021012201 |
4 | 30020232020300323 |
5 | 203141442323024 |
6 | 5553024051031 |
7 | 640632330646 |
oct | 141056106073 |
9 | 36564467181 |
10 | 13031214139 |
11 | 5587865069 |
12 | 2638163a77 |
13 | 12c89b04c8 |
14 | 8b8972a5d |
15 | 51406a744 |
hex | 308b88c3b |
13031214139 has 2 divisors, whose sum is σ = 13031214140. Its totient is φ = 13031214138.
The previous prime is 13031214103. The next prime is 13031214151. The reversal of 13031214139 is 93141213031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13031214139 - 221 = 13029116987 is a prime.
It is a super-2 number, since 2×130312141392 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13031214169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515607069 + 6515607070.
It is an arithmetic number, because the mean of its divisors is an integer number (6515607070).
Almost surely, 213031214139 is an apocalyptic number.
13031214139 is a deficient number, since it is larger than the sum of its proper divisors (1).
13031214139 is an equidigital number, since it uses as much as digits as its factorization.
13031214139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 28.
The spelling of 13031214139 in words is "thirteen billion, thirty-one million, two hundred fourteen thousand, one hundred thirty-nine".
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