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13031214103 is a prime number
BaseRepresentation
bin11000010001011100…
…01000110000010111
31020122011112021011101
430020232020300113
5203141442322403
65553024050531
7640632330565
oct141056106027
936564467141
1013031214103
115587865036
122638163a47
1312c89b049b
148b8972a35
1551406a71d
hex308b88c17

13031214103 has 2 divisors, whose sum is σ = 13031214104. Its totient is φ = 13031214102.

The previous prime is 13031214089. The next prime is 13031214139. The reversal of 13031214103 is 30141213031.

It is a weak prime.

It is an emirp because it is prime and its reverse (30141213031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13031214103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13031214403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515607051 + 6515607052.

It is an arithmetic number, because the mean of its divisors is an integer number (6515607052).

Almost surely, 213031214103 is an apocalyptic number.

13031214103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13031214103 is an equidigital number, since it uses as much as digits as its factorization.

13031214103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13031214103 its reverse (30141213031), we get a palindrome (43172427134).

The spelling of 13031214103 in words is "thirteen billion, thirty-one million, two hundred fourteen thousand, one hundred three".