Base | Representation |
---|---|
bin | 111100101011101010… |
… | …0110110010101110100 |
3 | 110110100210222021202010 |
4 | 1321113110312111310 |
5 | 4113340402232012 |
6 | 135510535244220 |
7 | 12262206410004 |
oct | 1712724662564 |
9 | 413323867663 |
10 | 130314102132 |
11 | 502a1a05775 |
12 | 21309b19670 |
13 | c399c9c396 |
14 | 64430b0004 |
15 | 35ca70ac3c |
hex | 1e57536574 |
130314102132 has 24 divisors (see below), whose sum is σ = 309803338656. Its totient is φ = 42618448288.
The previous prime is 130314102101. The next prime is 130314102143. The reversal of 130314102132 is 231201413031.
It is a junction number, because it is equal to n+sod(n) for n = 130314102099 and 130314102108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 102447558 + ... + 102448829.
It is an arithmetic number, because the mean of its divisors is an integer number (12908472444).
Almost surely, 2130314102132 is an apocalyptic number.
130314102132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
130314102132 is an abundant number, since it is smaller than the sum of its proper divisors (179489236524).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130314102132 is a wasteful number, since it uses less digits than its factorization.
130314102132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 204896447 (or 204896445 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 130314102132 its reverse (231201413031), we get a palindrome (361515515163).
The spelling of 130314102132 in words is "one hundred thirty billion, three hundred fourteen million, one hundred two thousand, one hundred thirty-two".
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