Base | Representation |
---|---|
bin | 1011110110100100000001… |
… | …1001100111011101100010 |
3 | 1201010211220021021122211020 |
4 | 2331221000121213131202 |
5 | 3202004024333424442 |
6 | 43414453500230310 |
7 | 2513350246525560 |
oct | 275510031473542 |
9 | 51124807248736 |
10 | 13032011233122 |
11 | 4174932662a62 |
12 | 156583623b396 |
13 | 736bb492b78b |
14 | 330a77610a30 |
15 | 178ed4b419ec |
hex | bda40667762 |
13032011233122 has 32 divisors (see below), whose sum is σ = 31539657439872. Its totient is φ = 3504406381824.
The previous prime is 13032011233117. The next prime is 13032011233133. The reversal of 13032011233122 is 22133211023031.
13032011233122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13032011233092 and 13032011233101.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9126057573 + ... + 9126059000.
It is an arithmetic number, because the mean of its divisors is an integer number (985614294996).
Almost surely, 213032011233122 is an apocalyptic number.
13032011233122 is an abundant number, since it is smaller than the sum of its proper divisors (18507646206750).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13032011233122 is a wasteful number, since it uses less digits than its factorization.
13032011233122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18252116602.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13032011233122 its reverse (22133211023031), we get a palindrome (35165222256153).
The spelling of 13032011233122 in words is "thirteen trillion, thirty-two billion, eleven million, two hundred thirty-three thousand, one hundred twenty-two".
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