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13032017 is a prime number
BaseRepresentation
bin110001101101…
…101001010001
3220112002120022
4301231221101
511314011032
61143153225
7215525135
oct61555121
926462508
1013032017
1173a1169
124445815
13291396b
141a333c5
151226512
hexc6da51

13032017 has 2 divisors, whose sum is σ = 13032018. Its totient is φ = 13032016.

The previous prime is 13031999. The next prime is 13032023. The reversal of 13032017 is 71023031.

13032017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10601536 + 2430481 = 3256^2 + 1559^2 .

It is a cyclic number.

It is not a de Polignac number, because 13032017 - 214 = 13015633 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13031986 and 13032004.

It is not a weakly prime, because it can be changed into another prime (13032037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516008 + 6516009.

It is an arithmetic number, because the mean of its divisors is an integer number (6516009).

Almost surely, 213032017 is an apocalyptic number.

It is an amenable number.

13032017 is a deficient number, since it is larger than the sum of its proper divisors (1).

13032017 is an equidigital number, since it uses as much as digits as its factorization.

13032017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 17.

The square root of 13032017 is about 3609.9885041368. The cubic root of 13032017 is about 235.3263430385.

Adding to 13032017 its reverse (71023031), we get a palindrome (84055048).

The spelling of 13032017 in words is "thirteen million, thirty-two thousand, seventeen".