Base | Representation |
---|---|
bin | 1011110110100100000110… |
… | …1001111111011110101111 |
3 | 1201010211221201221010021221 |
4 | 2331221001221333132233 |
5 | 3202004100232144043 |
6 | 43414455532004211 |
7 | 2513350623602056 |
oct | 275510151773657 |
9 | 51124851833257 |
10 | 13032032303023 |
11 | 41749435440a8 |
12 | 1565841300667 |
13 | 736bb90c7b86 |
14 | 330a7a33739d |
15 | 178ed69048ed |
hex | bda41a7f7af |
13032032303023 has 2 divisors, whose sum is σ = 13032032303024. Its totient is φ = 13032032303022.
The previous prime is 13032032303011. The next prime is 13032032303033. The reversal of 13032032303023 is 32030323023031.
It is a strong prime.
It is an emirp because it is prime and its reverse (32030323023031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13032032303023 - 225 = 13031998748591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13032032303033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516016151511 + 6516016151512.
It is an arithmetic number, because the mean of its divisors is an integer number (6516016151512).
Almost surely, 213032032303023 is an apocalyptic number.
13032032303023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032032303023 is an equidigital number, since it uses as much as digits as its factorization.
13032032303023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 25.
Adding to 13032032303023 its reverse (32030323023031), we get a palindrome (45062355326054).
The spelling of 13032032303023 in words is "thirteen trillion, thirty-two billion, thirty-two million, three hundred three thousand, twenty-three".
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