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13032050441 = 16421793621
BaseRepresentation
bin11000010001100010…
…10100111100001001
31020122020002202101212
430020301110330021
5203142201103231
65553054022505
7640642413104
oct141061247411
936566082355
1013032050441
115588286423
1226384a7a35
1312c8c14067
148b8b0d73b
1551418342b
hex308c54f09

13032050441 has 4 divisors (see below), whose sum is σ = 13032860484. Its totient is φ = 13031240400.

The previous prime is 13032050411. The next prime is 13032050453. The reversal of 13032050441 is 14405023031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6592790416 + 6439260025 = 81196^2 + 80245^2 .

It is a cyclic number.

It is not a de Polignac number, because 13032050441 - 210 = 13032049417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13032050411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 380390 + ... + 413231.

It is an arithmetic number, because the mean of its divisors is an integer number (3258215121).

Almost surely, 213032050441 is an apocalyptic number.

It is an amenable number.

13032050441 is a deficient number, since it is larger than the sum of its proper divisors (810043).

13032050441 is an equidigital number, since it uses as much as digits as its factorization.

13032050441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 810042.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 13032050441 its reverse (14405023031), we get a palindrome (27437073472).

The spelling of 13032050441 in words is "thirteen billion, thirty-two million, fifty thousand, four hundred forty-one".

Divisors: 1 16421 793621 13032050441