Base | Representation |
---|---|
bin | 10010111101101101011… |
… | …100010010001111101101 |
3 | 11121120211000211102200012 |
4 | 102331231130102033231 |
5 | 132322434033100442 |
6 | 2434404215143005 |
7 | 163103534420546 |
oct | 22755534221755 |
9 | 4546730742605 |
10 | 1303211221997 |
11 | 46276383a873 |
12 | 1906a2974a65 |
13 | 95b7a494ab9 |
14 | 4710bc554cd |
15 | 23d75cdd582 |
hex | 12f6d7123ed |
1303211221997 has 2 divisors, whose sum is σ = 1303211221998. Its totient is φ = 1303211221996.
The previous prime is 1303211221981. The next prime is 1303211222009. The reversal of 1303211221997 is 7991221123031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 717602128996 + 585609093001 = 847114^2 + 765251^2 .
It is a cyclic number.
It is not a de Polignac number, because 1303211221997 - 24 = 1303211221981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1303211271997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651605610998 + 651605610999.
It is an arithmetic number, because the mean of its divisors is an integer number (651605610999).
Almost surely, 21303211221997 is an apocalyptic number.
It is an amenable number.
1303211221997 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303211221997 is an equidigital number, since it uses as much as digits as its factorization.
1303211221997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 41.
The spelling of 1303211221997 in words is "one trillion, three hundred three billion, two hundred eleven million, two hundred twenty-one thousand, nine hundred ninety-seven".
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