Base | Representation |
---|---|
bin | 10010111101101101011… |
… | …111010011001011111011 |
3 | 11121120211002022120202001 |
4 | 102331231133103023323 |
5 | 132322434233343113 |
6 | 2434404244121431 |
7 | 163103544221566 |
oct | 22755537231373 |
9 | 4546732276661 |
10 | 1303212012283 |
11 | 46276422a5a5 |
12 | 1906a3096277 |
13 | 95b7a6b071c |
14 | 4710bdbd4dd |
15 | 23d75de77dd |
hex | 12f6d7d32fb |
1303212012283 has 2 divisors, whose sum is σ = 1303212012284. Its totient is φ = 1303212012282.
The previous prime is 1303212012281. The next prime is 1303212012287. The reversal of 1303212012283 is 3822102123031.
It is a weak prime.
It is an emirp because it is prime and its reverse (3822102123031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1303212012283 - 21 = 1303212012281 is a prime.
It is a super-2 number, since 2×13032120122832 (a number of 25 digits) contains 22 as substring.
Together with 1303212012281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1303212012281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651606006141 + 651606006142.
It is an arithmetic number, because the mean of its divisors is an integer number (651606006142).
Almost surely, 21303212012283 is an apocalyptic number.
1303212012283 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303212012283 is an equidigital number, since it uses as much as digits as its factorization.
1303212012283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 28.
The spelling of 1303212012283 in words is "one trillion, three hundred three billion, two hundred twelve million, twelve thousand, two hundred eighty-three".
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