13032132011233 has 4 divisors (see below), whose sum is σ = 13598746446528. Its totient is φ = 12465517575940.

The previous prime is 13032132011209. The next prime is 13032132011299. The reversal of 13032132011233 is 33211023123031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13032132011233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13032132011198 and 13032132011207.

It is not an unprimeable number, because it can be changed into a prime (13032132018233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 283307217613 + ... + 283307217658.

It is an arithmetic number, because the mean of its divisors is an integer number (3399686611632).

Almost surely, 2^{13032132011233} is an apocalyptic number.

It is an amenable number.

13032132011233 is a deficient number, since it is larger than the sum of its proper divisors (566614435295).

13032132011233 is an equidigital number, since it uses as much as digits as its factorization.

13032132011233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 566614435294.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13032132011233 its reverse (33211023123031), we get a palindrome (46243155134264).

The spelling of 13032132011233 in words is "thirteen trillion, thirty-two billion, one hundred thirty-two million, eleven thousand, two hundred thirty-three".