Search a number
-
+
1303221299153 is a prime number
BaseRepresentation
bin10010111101101110000…
…010101110011111010001
311121120211201210101221012
4102331232002232133101
5132322444123033103
62434405215140305
7163104016161164
oct22755602563721
94546751711835
101303221299153
114627694a29a4
121906a6214695
1395b7c5b2807
144710d319adb
1523d76b2e2d8
hex12f6e0ae7d1

1303221299153 has 2 divisors, whose sum is σ = 1303221299154. Its totient is φ = 1303221299152.

The previous prime is 1303221299111. The next prime is 1303221299179. The reversal of 1303221299153 is 3519921223031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1229741269969 + 73480029184 = 1108937^2 + 271072^2 .

It is a cyclic number.

It is not a de Polignac number, because 1303221299153 - 224 = 1303204521937 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1303221299153.

It is not a weakly prime, because it can be changed into another prime (1303221299753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651610649576 + 651610649577.

It is an arithmetic number, because the mean of its divisors is an integer number (651610649577).

Almost surely, 21303221299153 is an apocalyptic number.

It is an amenable number.

1303221299153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303221299153 is an equidigital number, since it uses as much as digits as its factorization.

1303221299153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 87480, while the sum is 41.

The spelling of 1303221299153 in words is "one trillion, three hundred three billion, two hundred twenty-one million, two hundred ninety-nine thousand, one hundred fifty-three".