1303221440042 has 4 divisors (see below), whose sum is σ = 1954832160066. Its totient is φ = 651610720020.

The previous prime is 1303221440011. The next prime is 1303221440047. The reversal of 1303221440042 is 2400441223031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1176897352801 + 126324087241 = 1084849^2 + 355421^2 .

It is a super-2 number, since 2×1303221440042² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1303221439993 and 1303221440020.

It is not an unprimeable number, because it can be changed into a prime (1303221440047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325805360009 + ... + 325805360012.

Almost surely, 2^{1303221440042} is an apocalyptic number.

1303221440042 is a deficient number, since it is larger than the sum of its proper divisors (651610720024).

1303221440042 is an equidigital number, since it uses as much as digits as its factorization.

1303221440042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 651610720023.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 1303221440042 its reverse (2400441223031), we get a palindrome (3703662663073).

The spelling of 1303221440042 in words is "one trillion, three hundred three billion, two hundred twenty-one million, four hundred forty thousand, forty-two".