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1303221440047 is a prime number
BaseRepresentation
bin10010111101101110000…
…011010000111000101111
311121120211202001120012111
4102331232003100320233
5132322444142040142
62434405222144451
7163104020316022
oct22755603207057
94546752046174
101303221440047
1146276958983a
121906a6282127
1395b7c631997
144710d3551b9
1523d76b5ae17
hex12f6e0d0e2f

1303221440047 has 2 divisors, whose sum is σ = 1303221440048. Its totient is φ = 1303221440046.

The previous prime is 1303221440011. The next prime is 1303221440111. The reversal of 1303221440047 is 7400441223031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1303221440047 - 239 = 753465626159 is a prime.

It is a super-2 number, since 2×13032214400472 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1303221440347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651610720023 + 651610720024.

It is an arithmetic number, because the mean of its divisors is an integer number (651610720024).

Almost surely, 21303221440047 is an apocalyptic number.

1303221440047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303221440047 is an equidigital number, since it uses as much as digits as its factorization.

1303221440047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 31.

Adding to 1303221440047 its reverse (7400441223031), we get a palindrome (8703662663078).

The spelling of 1303221440047 in words is "one trillion, three hundred three billion, two hundred twenty-one million, four hundred forty thousand, forty-seven".