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1303232100112 = 2481452006257
BaseRepresentation
bin10010111101101110101…
…011111011011100010000
311121120212111010011001201
4102331232223323130100
5132323004404200422
62434410242440544
7163104210034645
oct22755653733420
94546774104051
101303232100112
114627745aa908
121906a9963154
1395b818c4b07
144711092bdcc
1523d77a64727
hex12f6eafb710

1303232100112 has 10 divisors (see below), whose sum is σ = 2525012193998. Its totient is φ = 651616050048.

The previous prime is 1303232100089. The next prime is 1303232100119. The reversal of 1303232100112 is 2110012323031.

It can be written as a sum of positive squares in only one way, i.e., 1065552449536 + 237679650576 = 1032256^2 + 487524^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 1303232100112.

It is not an unprimeable number, because it can be changed into a prime (1303232100119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40726003113 + ... + 40726003144.

Almost surely, 21303232100112 is an apocalyptic number.

It is an amenable number.

1303232100112 is a deficient number, since it is larger than the sum of its proper divisors (1221780093886).

1303232100112 is an equidigital number, since it uses as much as digits as its factorization.

1303232100112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81452006265 (or 81452006259 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1303232100112 its reverse (2110012323031), we get a palindrome (3413244423143).

The spelling of 1303232100112 in words is "one trillion, three hundred three billion, two hundred thirty-two million, one hundred thousand, one hundred twelve".

Divisors: 1 2 4 8 16 81452006257 162904012514 325808025028 651616050056 1303232100112