13032412004121 has 4 divisors (see below), whose sum is σ = 17376549338832. Its totient is φ = 8688274669412.

The previous prime is 13032412004077. The next prime is 13032412004147. The reversal of 13032412004121 is 12140021423031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13032412004121 - 2⁹ = 13032412003609 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13032412004091 and 13032412004100.

It is not an unprimeable number, because it can be changed into a prime (13032412004191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2172068667351 + ... + 2172068667356.

It is an arithmetic number, because the mean of its divisors is an integer number (4344137334708).

Almost surely, 2^{13032412004121} is an apocalyptic number.

It is an amenable number.

13032412004121 is a deficient number, since it is larger than the sum of its proper divisors (4344137334711).

13032412004121 is an equidigital number, since it uses as much as digits as its factorization.

13032412004121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4344137334710.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 13032412004121 its reverse (12140021423031), we get a palindrome (25172433427152).

The spelling of 13032412004121 in words is "thirteen trillion, thirty-two billion, four hundred twelve million, four thousand, one hundred twenty-one".